I= player 1
My opponent = player 2
I played the rock, scissors, and paper on the website. In this game, your opponent and you will have 3 strategies to choose (rock, paper, and scissor). The units in matrix represent the loss (-1), win (1), and equal (0). For example, if I chose rock and my opponent chose rock as well, we both were equal and hence received (0,0). But if I still chose rock and my opponent changed to paper. I would lose and my opponent won and hence the matrix would be (-1,1). What if I still continued playing with rock and my opponent changed to scissors, I would win and my opponent would lose (1, -1). This game is quite interesting as there is no dominant strategy; the win, lose, and equal are contributed equally through the 3 choices. What I mean here is that for my case, if I would always choose to play rock and would never change the strategy no matter what my opponent chose. The total utility will be 0. And this applies to the rest of the strategies. My opponent also has none of dominant strategy. There’s no Nash equilibrium as well. And well, when you playing this game, the guessing was such a big matter because you played again the computer, which just gives you random choices.